There are two types of situations of concern. The first is one with an
x-ray, , at a time
, that has a certain pattern
. This pattern is the pattern of a broken leg.
We define a universal , the universal of situations with an x-ray
of a broken leg, in the following way:
![]() |
|||
![]() |
|||
![]() ![]() ![]() ![]() |
The situation is then defined as follows, where
is the x-ray
and
the time the x-ray has been taken.
![]() |
|||
![]() ![]() |
|||
![]() ![]() ![]() |
|||
![]() |
Now is an anchor defined on
and
, such that
and
. Now we obtain
![]() |
|||
![]() |
![]() |
![]() ![]() ![]() ![]() |
|
![]() |
![]() ![]() ![]() ![]() |
||
![]() |
![]() ![]() ![]() ![]() |
||
![]() |
![]() |
Then is the following proposition:
![]() ![]() ![]() |
|||
![]() |
![]() ![]() ![]() |
||
![]() |
![]() ![]() ![]() |
This proposition is the pure information carried by the situation ,
namely the proposition, that in some situation
there has to be a
dog
, and
is the x-ray of
at time
.
Let us now see what we will obtain using the second type of constraint.
Let the type be the same as before,
Has-broken-leg
and
Is-xray-of
, and
.
The universal is the same as above.
We could state that the described situation is the instance of another universal, a universal of situations with an x-ray of a broken leg of some person. Or we could define an additional universal and say that this situation is also an instance of another universal, the universal of situations with an x-ray of an individual. Again for the sake of simplicity we omit this.
The situation is then defined as follows, where
and
are
as before, and
is assigned to the dog Jackie.
![]() |
|||
![]() ![]() |
|||
![]() ![]() ![]() |
|||
![]() ![]() |
|||
![]() |
Now is an anchor defined on
and
as well as
, with
,
and
,
has to assign
to the dog
Jackie,
.
Now we obtain the following.
![]() |
![]() |
![]() ![]() ![]() ![]() |
|
![]() |
![]() ![]() ![]() ![]() |
||
![]() |
![]() ![]() ![]() ![]() |
||
![]() |
![]() |
||
![]() |
![]() |
![]() ![]() |
|
![]() |
![]() ![]() |
||
![]() |
![]() ![]() |
||
![]() |
![]() |
Now we will obtain the proposition
![]() ![]() |
This is the information we wanted to obtain out of the described situation.
leechuck 2005-04-19